JavaPython:Hulk

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Redaktsioon seisuga 30. jaanuar 2016, kell 07:45 kasutajalt Triin (arutelu | kaastöö)
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Java vs Python

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Java Python
<syntaxhighlight lang="java" line="1" >

//hashset HashSet<String> aSet = new HashSet<String>(); aSet.add("aaaa"); aSet.add("bbbb"); aSet.add("cccc"); aSet.add("dddd");

//iterate over set Iterator<String> iterator = aSet.iterator(); while (iterator.hasNext()) { System.out.print(iterator.next() + " "); }

HashSet<String> bSet = new HashSet<String>(); bSet.add("eeee"); bSet.add("ffff"); bSet.add("gggg"); bSet.add("dddd");

//check if bSet is a subset of aSet boolean b = aSet.containsAll(bSet);

//union - transform aSet //into the union of aSet and bSet aSet.addAll(bSet);

//intersection - transforms aSet //into the intersection of aSet and bSet aSet.retainAll(bSet);

//difference - transforms aSet //into the (asymmetric) set difference // of aSet and bSet. aSet.removeAll(bSet); </syntaxhighlight>

<syntaxhighlight lang="python" line="2" >

aSet = set() aSet = set("one") # a set containing three letters

  1. set(['e', 'o', 'n'])

aSet = set(['one', 'two', 'three'])

  1. set(['three', 'two', 'one'])
  2. a set containing three words
  1. iterate over set

for v in aSet:

   print v

bSet = set(['three','four', 'five'])

  1. union

cSet = aSet | bSet

  1. set(['four', 'one', 'five', 'three', 'two'])
  1. intersection

dSet = aSet & bSet

  1. find elements in aSet not bSet

eSet = aSet.difference(bSet)

  1. add element

bSet.add("six")

  1. set(['four', 'six', 'five', 'three'])

</syntaxhighlight>